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x^2-4x-1440=0
a = 1; b = -4; c = -1440;
Δ = b2-4ac
Δ = -42-4·1·(-1440)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-76}{2*1}=\frac{-72}{2} =-36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+76}{2*1}=\frac{80}{2} =40 $
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